In this Python program, we will leverage recursion to count the occurrences of elements within a linked list. This program will provide you with a deeper understanding of recursion and how it can be applied to solve problems involving linked lists.

## Problem statement

The challenge is to write a Python program that counts the occurrences of elements in a given linked list using recursion. By employing recursion, you can efficiently traverse the linked list and tally the number of occurrences of each element.

## Python Program to Count the Occurrences of Elements in a Linked List using Recursion

class Node: def __init__(self, data): self.data = data self.next = None class LinkedList: def __init__(self): self.head = None def insert(self, data): new_node = Node(data) if not self.head: self.head = new_node else: current = self.head while current.next: current = current.next current.next = new_node def count_occurrences(self, head, target): if not head: return 0 if head.data == target: return 1 + self.count_occurrences(head.next, target) else: return self.count_occurrences(head.next, target) # Example usage if __name__ == "__main__": linked_list = LinkedList() elements = [2, 4, 3, 4, 2, 5, 4] for element in elements: linked_list.insert(element) target_element = 4 occurrences = linked_list.count_occurrences(linked_list.head, target_element) print(f"Occurrences of {target_element}: {occurrences}")

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