C# Program to swap two numbers without using temporary variable

Introduction

This program in C# developed using .NET Framework and Visual Studio  will demonstrate how to swap numbers without using temporary variable.

C# Program to swap two numbers without using temporary variable

using System;

namespace GinktageConsoleApp
{
    internal class Program
    {
        private static void Main(string[] args)
        {
            int Input1, Input2;

            Console.Write("Input the First Number ");

            Input1 = int.Parse(Console.ReadLine());

            Console.Write("\nInput the Second Number : ");

            Input2 = int.Parse(Console.ReadLine());

            Input1 = Input1 + Input2;
            Input2 = Input1 - Input2;
            Input1 = Input1 - Input2;

            Console.Write("\nResult after Swapping the two number : ");

            Console.Write("\nFirst Number : " + Input1);

            Console.Write("\nSecond Number : " + Input2);

            Console.ReadLine();
        }
    }
}

image

Leave A Reply

Your email address will not be published. Required fields are marked *

You May Also Like

C# Compiler Error CS0442 – ‘Property’: abstract properties cannot have private accessors Reason for the Error You’ll get this error...
This is a really simple one . Below is a simple example of an enum called “Designation” defined with the...
This blog post explain the usage of the Checked Block in .NET and how you can use them in Visual...