In this post, you will learn how to Find Transpose of a Matrix using C++ Programming language.
This lesson will teach you how to Find Transpose of a Matrix, with mathematical function, and the for loop statement using the C++ Language. Let’s look at the below source code.
How to Find Transpose of a Matrix?
RUN CODE SNIPPETSource Code
#include<iostream> using namespace std; int main() { int transpose[10][10], r=3, c=2, i, j; int a[3][3] = { {1, 2} , {3, 4} , {5, 6} }; cout<<"The matrix is:"<<endl; for(i=0; i<r; ++i) { for(j=0; j<c; ++j) cout<<a[i][j]<<" "; cout<<endl; } cout<<endl; for(i=0; i<r; ++i) for(j=0; j<c; ++j) { transpose[j][i] = a[i][j]; } cout<<"The transpose of the matrix is:"<<endl; for(i=0; i<c; ++i) { for(j=0; j<r; ++j) cout<<transpose[i][j]<<" "; cout<<endl; } return 0; }
Output
The matrix is: 1 2 3 4 5 6 The transpose of the matrix is: 1 3 5 2 4 6
The statements #include<iostream>, using namespace std, int main are the main factors that support the function of the source code.
Now we can look into the working and layout of the code’s function.
- Declare the variables transpose, r, c, i, j, a as integers. The variables r, c hold the size of the rows and columns of the transpose array. Declare the variable a as in array with the size of the array in [ ] and assign the value of the array in { }
- Declare a for loop with the condition
(i=0; i<r; ++i)
to verify the number of rows and declare another for loop with the condition(j=0; j<c; ++j)
to verify the number of columns, then using the output statement cout display the array a. - Declare two for loop statements with conditions to verify the number of the rows and columns. In the body of the loop include the function
transpose[j][i] = a[i][j]
where the row variable and the column variable is interchanged. This function performs the Transpose of the Matrix. - Declare a final for loop with the condition to verify the number of rows and columns, with a another for loop in the body of the loop and display the output/answer using the function cout.