Curriculum
In this tutorial, you will learn how to use the SQL COUNT function to get the number of items in a group.
The SQL COUNT function is an aggregate function that returns the number of rows returned by a query. You can use the COUNT function in the SELECT statement to get the number of employees, the number of employees in each department, the number of employees who hold a specific job, etc.
The following illustrates the syntax of the SQL COUNT function:
COUNT([ALL | DISTINCT] expression);
The result of the COUNT function depends on the argument that you pass to it.
ALL keyword will include the duplicate values in the result. For example, if you have a group (1, 2, 3, 3, 4, 4) and apply the COUNT function, the result is 6. By default, the COUNT function uses the ALL keyword whether you specify it or not.DISTINCT keyword counts only unique values. For example, the COUNT function returns 4 if you apply it to the group (1, 2, 3, 3, 4, 4).Another form of the COUNT function that accepts an asterisk (*) as the argument is as follows:
COUNT(*)
The COUNT(*) function returns the number of rows in a table in a query. It counts duplicate rows and rows that contain null values.
Let’s take some examples to see how the COUNT function works. We will use the employees table in the sample database for demonstration purposes:
The following example uses the COUNT(*) function to get the number of rows from the employees table:
SELECT
COUNT(*)
FROM
employees;
The following example uses the COUNT(*) function to count employees who work in the department with id 6:
SELECT
COUNT(*)
FROM
employees
WHERE
department_id = 6;
In this example:
WHERE clause filter department with id 6.COUNT(*) function returns the number of rows from the employees table with the value in the department id 6.The following example uses the COUNT(*) function to get the number of employees with the job id 9:
SELECT
COUNT(*)
FROM
employees
WHERE
job_id = 9;
How it works.
WHERE clause includes the rows from the employees table with the job id 9.COUNT(*) returns the number of rows from the employees table with the job id 9The following example uses the AS keyword to assign the COUNT(*) a column alias:
SELECT
COUNT(*) as employee_count
FROM
employees
WHERE
job_id = 9;
The following example uses the COUNT function with GROUP BY clause to find the number of employees for each department:
SELECT
department_id,
COUNT(*)
FROM
employees
GROUP BY
department_id;
How it works:
GROUP BY clause groups the rows in the employees table by the department id.COUNT(*) function returns the number of rows for each groupThe following example uses the COUNT(*) function to get the number of employees by department. Also, it uses an INNER JOIN clause to include the department name in the result set:
SELECT
e.department_id,
department_name,
COUNT(*)
FROM
employees e
INNER JOIN departments d
ON d.department_id = e.department_id
GROUP BY
e.department_id,
department_name;
The following example uses the ORDER BY clause to sort the number of employees by department:
SELECT
e.department_id,
department_name,
COUNT(*)
FROM
employees e
INNER JOIN departments d ON d.department_id = e.department_id
GROUP BY
e.department_id
ORDER BY
COUNT(*) DESC;
The following example returns the number of employees by department. Also, it uses a HAVING clause to select only departments that have more than five employees:
SELECT
e.department_id,
department_name,
COUNT(*)
FROM
employees e
INNER JOIN departments d ON d.department_id = e.department_id
GROUP BY
e.department_id
HAVING
COUNT(*) > 5
ORDER BY
COUNT(*) DESC;
The following example uses the COUNT to get the number of values in the job_id column in the employees table:
SELECT
COUNT(job_id)
FROM
employees;
The query returns 40 which includes the duplicate values. To remove the duplicates, you use the DISTINCT keyword to the COUNT function as follows:
SELECT
COUNT(DISTINCT job_id)
FROM
employees;
The query returns 40 which includes the duplicate values. To remove the duplicates, you use the DISTINCT keyword to the COUNT function as follows:
SELECT
COUNT(DISTINCT job_id)
FROM
employees;
The following example uses the COUNT function with the DISTINCT keyword to get the number of managers:
SELECT
COUNT(DISTINCT manager_id)
FROM
employees;